看到有人问如图的程序，就去写了几行代码，顺便复习一下条件语句和ASCII码

 

1 import java.util.Scanner; 2 public class test1 { 3  4     public static void main(String[] args)  5     { 6         Scanner sc = new Scanner(System.in); 7         System.out.print("输入一个ASCII数值："); 8         int ascii = sc.nextInt(); 9         sc.close();10         char ch = (char)ascii;11         //在‘a’~‘z’转成‘A’~‘Z’12         if(ch >= 'a' && ch <= 'z')13         {14             System.out.println((char)(ch-32));15         }16         //在‘A’~‘Z’转成‘a’~‘z’17         else if(ch >= 'A' && ch <= 'Z')18         {19             System.out.println((char)(ch+32));20         }21         //在‘0’~‘9’输出0~922         else if(ch >= '0' && ch <= '9')23         {24             System.out.println(ch);25         }26         //输出“+ - * /”27         else if(ch == '+' || ch== '-' || ch == '*' || ch == '/')28         {29             System.out.println("属于算术运算符");30         }31         //输出“非法字符”32         else33         {34             System.out.println("非法字符");35         }36     }37 }

 

作者：耑新新，发布于  

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